Armstrong Number In Java

Armstrong Number is a number that is the sum of its own digits each raised to the power of the number of digits.

Example:

1³+5³+3³=153 which is same as given number 153., and 3 is the number of digits.

1⁴+6⁴+3⁴+4⁴=1634 which is same as given number 1634., and 4 is the number of digits.

package my.test;

public class ArmstrongNumber {

	public static void main(String[] args) {
		
		System.out.println("Is 153 ArmsStrong Number: " + isArmstrongNumber(153));
		System.out.println("Is 1634 ArmsStrong Number: " + isArmstrongNumber(1634));
		System.out.println("Is 93084 ArmsStrong Number: " + isArmstrongNumber(93084));
		System.out.println("Is 9800817 ArmsStrong Number: " + isArmstrongNumber(9800817));
		System.out.println("Is 407 ArmsStrong Number: " + isArmstrongNumber(407));
		System.out.println("Is 406 ArmsStrong Number: " + isArmstrongNumber(406));
	}
	
	public static boolean isArmstrongNumber(int number) {
		if(number>0) {
			// Find number of digits in the given number..
			int temp = number;
			int numberOfDigits = 0;
			while(temp>0) {
				temp =temp/10;
				numberOfDigits++;
			}
			//Power each digits with the number of digits..
			int temp2 = number;
			int calcNumber = 0;
			while(temp2>0) {
				calcNumber = (int) (calcNumber + Math.pow((temp2%10), numberOfDigits));
				temp2 = temp2/10;
			}
			if(calcNumber == number) {
				return true;
			}
		}
		return false;
	}
}

package my.test;

public class ArmstrongNumber {

public static void main(String[] args) {

System.out.println("Is 153 ArmsStrong Number: " + isArmstrongNumber(153));

System.out.println("Is 1634 ArmsStrong Number: " + isArmstrongNumber(1634));

System.out.println("Is 93084 ArmsStrong Number: " + isArmstrongNumber(93084));

System.out.println("Is 9800817 ArmsStrong Number: " + isArmstrongNumber(9800817));

System.out.println("Is 407 ArmsStrong Number: " + isArmstrongNumber(407));

System.out.println("Is 406 ArmsStrong Number: " + isArmstrongNumber(406));

}

public static boolean isArmstrongNumber(int number) {

if(number>0) {

// Find number of digits in the given number..

int temp = number;

int numberOfDigits = 0;

while(temp>0) {

temp =temp/10;

numberOfDigits++;

}

//Power each digits with the number of digits..

int temp2 = number;

int calcNumber = 0;

while(temp2>0) {

calcNumber = (int) (calcNumber + Math.pow((temp2%10), numberOfDigits));

temp2 = temp2/10;

}

if(calcNumber == number) {

return true;

}

return false;

}

Output:

Is 153 ArmsStrong Number: true
Is 1634 ArmsStrong Number: true
Is 93084 ArmsStrong Number: true
Is 9800817 ArmsStrong Number: true
Is 407 ArmsStrong Number: true
Is 406 ArmsStrong Number: false

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